{"id":7284,"date":"2026-07-23T07:36:01","date_gmt":"2026-07-23T07:36:01","guid":{"rendered":"https:\/\/assignmenttask.com\/answers\/?p=7284"},"modified":"2026-07-23T07:43:00","modified_gmt":"2026-07-23T07:43:00","slug":"what-is-the-product-of-the-following-reaction","status":"publish","type":"post","link":"https:\/\/assignmenttask.com\/answers\/what-is-the-product-of-the-following-reaction\/","title":{"rendered":"What is the Product of the Following Reaction?"},"content":{"rendered":"

What is the Product of the Following Reaction?<\/strong><\/h2>\n

\"\"<\/a><\/p>\n

How Can I Solve No. 31?<\/span><\/p>\n

Solution:<\/strong><\/span> From the image, the substrate appears to be 2 equivalents of furfural (furan-2-carbaldehyde) treated with:<\/span><\/p>\n

OH\u207b (base), added slowly<\/span><\/p>\n

H\u2082O<\/span><\/p>\n

This is a classic aldol reaction.<\/span><\/p>\n

Step 1: Identify the type of reaction<\/strong><\/p>\n

Furfural has an aldehyde but no \u03b1-hydrogens (the carbon next to the CHO group is part of the aromatic furan ring).<\/span><\/p>\n

Since it cannot form an enolate, it cannot undergo a self-aldol condensation.<\/span><\/p>\n

Step 2: What happens under a strong base?<\/strong><\/p>\n

An aldehyde with no \u03b1-hydrogens undergoes the Cannizzaro reaction instead.<\/span><\/p>\n

The Cannizzaro reaction disproportionates 2 molecules of the aldehyde:<\/span><\/p>\n

2RCHO+OH\u2212\u2192RCH2OH+RCOO\u2212<\/span><\/p>\n

After the water workup, the products remain:<\/span><\/p>\n

Furfuryl alcohol (reduction product)<\/span><\/p>\n

Furoate (or furoic acid after acidification) (oxidation product)<\/span><\/p>\n

Since the workup shown is only H\u2082O, the carboxylate salt is usually written as furoate.<\/span><\/p>\n

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\"Order<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

What is the Product of the Following Reaction? How Can I Solve No. 31? Solution: From the image, the substrate appears to be 2 equivalents of furfural (furan-2-carbaldehyde) treated with: OH\u207b (base), added slowly H\u2082O This is a classic aldol reaction. Step 1: Identify the type of reaction Furfural has an aldehyde but no \u03b1-hydrogens (the carbon next to the CHO group is part of the aromatic furan ring). Since it cannot form an enolate, it cannot undergo a self-aldol condensation. Step 2: What happens under a strong base? An aldehyde with no \u03b1-hydrogens undergoes the Cannizzaro reaction instead. The Read More …<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[212],"tags":[],"class_list":["post-7284","post","type-post","status-publish","format-standard","hentry","category-chemistry"],"yoast_head":"\nWhat is the Product of the Following Reaction?<\/title>\n<meta name=\"description\" content=\"Want to get assignment answers online by academic writers? 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